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x*10^-3x=1000
We move all terms to the left:
x*10^-3x-(1000)=0
We add all the numbers together, and all the variables
-3x+x*10^-1000=0
Wy multiply elements
10x^2-3x-1000=0
a = 10; b = -3; c = -1000;
Δ = b2-4ac
Δ = -32-4·10·(-1000)
Δ = 40009
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{40009}}{2*10}=\frac{3-\sqrt{40009}}{20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{40009}}{2*10}=\frac{3+\sqrt{40009}}{20} $
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